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How much land does solar need per kW

A fixed-tilt ground-mount array with modern panels needs about 6 to 12 m² of array area per kW at mid latitudes, or roughly 2 to 4 acres per MW including access and setbacks. Here is where those numbers come from and what changes them.

The formula

Land per kW (m²) = 1,000 ÷ (module W/m² × ground coverage ratio) ÷ site use factorGround coverage ratio (GCR): sloped table length ÷ row pitch. Site use factor: the share of the site that ends up under panels after roads, setbacks, fencing and equipment pads.

A 655 W module (2.382 m × 1.134 m), today's mainstream size, is about 243 W/m². Put two of them in portrait on each table (about 4.8 m of slope), face the equator, and size the rows for no shading at the times shown:

LatitudeTiltShade-freeRow pitchArray onlySite (80 % use)
35°20°Solstice noon7.2 m6.2 m²/kW1.9 acres/MW
35°30°Solstice 9:00 to 15:009.6 m8.3 m²/kW2.6 acres/MW
40°20°Solstice noon7.8 m6.7 m²/kW2.1 acres/MW
40°30°Solstice 9:00 to 15:0011.3 m9.7 m²/kW3.0 acres/MW
45°30°Solstice 9:00 to 15:0014.1 m12.2 m²/kW3.8 acres/MW

You will often see "5 to 7 acres per MW" for utility plants. That figure includes older, less efficient modules, trackers, wide setbacks and everything else inside the fence. For a home or farm ground mount with current panels, the table above is closer.

What changes the land you need

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FAQ

How many acres for a 1 MW solar farm?

With modern panels on fixed racks, about 2 to 4 acres for the array and its access. Plan for more if the site is irregular or setbacks are large.

How much space does a 10 kW ground mount need?

About 60 to 120 m² (650 to 1,300 sq ft) of ground, depending on tilt and whether it is one row or several.

Does a roof need the same area?

No. Panels flush on a sloped roof need no row gaps, so about 4.2 to 4.7 m² per kW is enough.